找到全部一致连续的整函数并证明
Acceptance criteria set:
1. A precise statement of the theorem is given: the set of all entire functions f: ℂ → ℂ that are uniformly continuous on ℂ is exactly { f(z) = az + b | a, b ∈ ℂ }.
2. Definitions of 'entire function' and 'uniformly continuous on ℂ' are explicitly stated and used consistently throughout the proof.
3. Proof that every function of the form f(z) = az + b (a, b ∈ ℂ) is entire and uniformly continuous on ℂ, with explicit ε-δ argument for uniform continuity.
4. Proof that if f is entire and uniformly continuous on ℂ, then f must be a polynomial of degree at most 1, using Cauchy's estimates or Liouville's theorem on the derivative, with all estimates fully justified and no appeal to intuition.
5. Proof that no entire function of degree ≥ 2 (e.g., z², e^z, sin z) is uniformly continuous on ℂ, by exhibiting explicit sequences violating the uniform continuity condition or by growth-rate arguments with explicit constants.
6. The complete argument is self-contained: every lemma invoked (Cauchy integral formula, Liouville's theorem, etc.) is either proved in-line or cited with a precise reference, all quantifiers are explicit, and no step relies on 'it is clear that', 'obviously', or similar gaps.